請問一下，我有一個相除的式子，結果可能不會整除 有沒有一個函數可以滿足下列需求 1/3=1, 2/3=1, 3/3=1, 4/3=2, 5/3=2, 6/3=2,.....

int i=1,j=3; int a,b; a=1/3; b=1%3; if(b > 0) a ; 這樣就無條件進入啦

抱歉打錯 int i=1,j=3; int a,b; a=i/j; b=i%j; if(b > 0) a ; 這樣就無條件進入啦

我現在也是用這個方式 不過我想應該有一個函式可以做這件事吧 下面是我用的方法 int a,b; a = 1/3; if ( 1%3 != 0 ) a ;

for(int i=1; i<100; i  )
  int k := (i-1) / 3   1;
  

您好，以下節錄自Delphi Help..跟C Builder應該是一樣的 Truncates a real number to an integer. Delphi syntax: function Trunc(X: Extended): Int64; Rounds variables toward negative infinity. Delphi syntax: function Floor(const X: Extended): Integer; Description Call Floor to obtain the highest integer less than or equal to X. For example: Floor(-2.8) = -3 Floor(2.8) = 2 Floor(-1.0) = -1 Rounds variables up toward positive infinity. function Ceil(const X: Extended):Integer; Description Call Ceil to obtain the lowest integer greater than or equal to X. The absolute value of X must be less than MaxInt. For example: Ceil(-2.8) = -2 Ceil(2.8) = 3 Ceil(-1.0) = -1 Returns the value of X rounded to the nearest whole number. Delphi syntax: function Round(X: Extended): Int64; Rounds a floating-point value to a specified digit or power of ten using ?anker? rounding? function RoundTo(const AValue: Double; const ADigit: TRoundToRange): Double; Expression Value RoundTo(1234567, 3) 1234000 RoundTo(1.234, -2) 1.23 RoundTo(1.235, -2) 1.24 RoundTo(1.245, -2) 1.24

引言: for(int i=1; i<100; i ) int k = (i-1) / 3 1;

我覺得這方法不錯，但就怕(i-1) < 0會有問題 例(0-1)/3 1 => 1 StrongLemon的方式我試過了，可以滿足需求 ceil((double)0/(double)3)=0, ceil((double)1/(double)3)=1, ceil((double)2/(double)3)=1,