8051矩陣按鍵詢問 |
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Onlyfire
一般會員 發表:1 回覆:0 積分:0 註冊:2019-04-14 發送簡訊給我 |
各位先進大家好,小弟我最近在學習8051單晶片,透過YouTube上的教學影片,但是當學到鍵盤這一章節時卡住了,
主要是卡在鍵盤鍵值表的使用上,因為我搞不太懂為何在影片上的鍵值表的設定,同時我寫出的程式也無法正確地作動,希望各位前輩能夠幫忙解析,謝謝! 程式主要是做一個簡易的加法計算器,我比較搞不懂在教學影片中鍵值表如下, unsigned char code KeycodeMap[4][4] = { //鍵盤鍵值表 {0x31, 0x32, 0x33, 0x26}, //1, 2, 3, {0x34, 0x34, 0x36, 0x25}, //4, 5, 6, {0x37, 0x38, 0x39, 0x28}, //7, 8, 9, {0x30, 0x1B, 0x0D, 0x27} //0, ESC, Enter, }; 但是我查了網路上對於鍵值表相關資訊,大概都會是0xEE, 0xEB...等表示方式, 教學影片上的矩陣鍵盤電路如附件,因此想請問各位前輩,這樣的設定有甚麼樣的意義嗎?為何會跟我查到的不太一樣, 另外我的程式上是否有錯誤,為何按鍵一直沒辦法成功驅動呢? 完整的程式如下: #include sbit Key_in_1 = P2^7; sbit Key_in_2 = P2^6; sbit Key_in_3 = P2^5; sbit Key_in_4 = P2^4; sbit Key_out_1 = P2^0; sbit Key_out_2 = P2^1; sbit Key_out_3 = P2^2; sbit Key_out_4 = P2^3; unsigned char code Segment [] = { 0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, //0, 1, 2, 5, 4, 5, 6, 7 0x80, 0x98, 0x88, 0x83, 0xC6, 0xA1, 0x86, 0x8E //8, 9, A, B, C, D, E, F }; unsigned char Keysta [4][4] ={ {1,1,1,1}, {1,1,1,1}, {1,1,1,1}, {1,1,1,1} }; unsigned char LedBuffer[6] = { 0xFF, 0xFF, 0xFF, 0xFF, 0xFF, 0xFF }; unsigned char code KeycodeMap[4][4] = { //鍵盤鍵值表 {0x31, 0x32, 0x33, 0x26}, {0x34, 0x34, 0x36, 0x25}, {0x37, 0x38, 0x39, 0x28}, {0x30, 0x1B, 0x0D, 0x27} }; void KeyDriver(); void main() { EA = 1; TMOD = 0x01; TH0 = 0xFC; TL0 = 0x67; TR0 = 1; ET0 = 1; LedBuffer[0] = Segment[0]; while(1) { KeyDriver(); } } void shownumber(unsigned long num) { unsigned char buffer[6]; signed char i = 0; //define signed due to i may be negative for(i=0; i<6; i ) { buffer[i] = num % 10; num = num / 10; } for(i=5; i>=1; i--) //Not show the high number { if(buffer[i] == 0) { LedBuffer[i] = 0xFF; } else break; } for(; i>=0; i--) { LedBuffer[i] = Segment[buffer[i]]; } } void KeyAction(unsigned char keycode) { static unsigned long result = 0; static unsigned long addend = 0; if((keycode >= 0x30) && (keycode <= 0x39)) { addend = (addend*10) (keycode - 0x30); shownumber(addend); } else if(keycode == 0x26) { result = addend; addend = 0; shownumber(result); } else if(keycode == 0x0D) { result = addend; addend = 0; shownumber(result); } else if(keycode == 0x1B) { addend = 0; result = 0; shownumber(addend); } } void KeyDriver() { unsigned char i, j; static unsigned char backup [4][4] = { {1,1,1,1}, {1,1,1,1}, {1,1,1,1}, {1,1,1,1} }; for(i=0; i<4; i ) //i表in { for(j=0; j<4; j ) //j表out { if(backup[i][j] != Keysta[i][j]) { if(backup[i][j] == 0x00) { KeyAction(KeycodeMap[i][j]); //可表示出1-16 } backup[i][j] = Keysta[i][j]; //更新目前按鍵 } } } } void KeyScan() { static unsigned char keyout = 0; unsigned char i = 0; unsigned char Keybuf[4][4] = { {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF}, {0xFF, 0xFF, 0xFF, 0xFF} }; Keybuf[keyout][0] = (Keybuf[keyout][0] << 1) | Key_in_1; Keybuf[keyout][1] = (Keybuf[keyout][1] << 1) | Key_in_2; Keybuf[keyout][2] = (Keybuf[keyout][2] << 1) | Key_in_3; Keybuf[keyout][3] = (Keybuf[keyout][3] << 1) | Key_in_4; for(i=0; i<4; i ) { if((Keybuf[keyout][i] & 0x0F) == 0x00) { Keysta[keyout][i] = 0; } else if((Keybuf[keyout][i] & 0x0F) == 0x0F) { Keysta[keyout][i] = 1; } } keyout ; keyout = keyout & 0x03; switch(keyout) { case 0: Key_out_4 = 1; Key_out_1 = 0; break; case 1: Key_out_1 = 1; Key_out_2 = 0; break; case 2: Key_out_2 = 1; Key_out_3 = 0; break; case 3: Key_out_3 = 1; Key_out_4 = 0; break; default: break; } } void LedScan() { static unsigned char i = 0; P0 = 0xFF; switch (i) { case 0: P1 = 0x00; i ; P0 = LedBuffer[0]; break; case 1: P1 = 0x00; i ; P0 = LedBuffer[1]; break; case 2: P1 = 0x00; i ; P0 = LedBuffer[2]; break; case 3: P1 = 0x00; i ; P0 = LedBuffer[3]; break; case 4: P1 = 0x00; i ; P0 = LedBuffer[4]; break; case 5: P1 = 0x00; i=0; P0 = LedBuffer[5]; break; default:break; } } void InterruptTimer0() interrupt 1 { TH0 = 0xFC; TL0 = 0x67; LedScan(); KeyScan(); } |
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