我想用亂數產生一個[8][8]的矩陣再把它顯示成影像,像素就只有黑白二種,程式如下:
int pix=random(2);
int a1[8][8]={{pix,pix,pix,pix,pix,pix,pix,pix},{pix,pix,pix,pix,pix,pix,pix,pix},
{pix,pix,pix,pix,pix,pix,pix,pix},{pix,pix,pix,pix,pix,pix,pix,pix},
{pix,pix,pix,pix,pix,pix,pix,pix},{pix,pix,pix,pix,pix,pix,pix,pix},
{pix,pix,pix,pix,pix,pix,pix,pix},{pix,pix,pix,pix,pix,pix,pix,pix}};
for(int j=0;jPicture->Bitmap->Height;j )
{
for(int i=0;iPicture->Bitmap->Width;i )
{
if(a1[i%8][j%8]==1)
Image3->Canvas->Pixels[i][j]=255;
else
Image3->Canvas->Pixels[i][j]=0;
}
}
我知道這個程式看起來很笨且沒有反應,不知道少了什麼??
能不能麻煩高手指正我,多謝多謝^^

------
加強磨鍊

<textarea class="cpp" rows="10" cols="60" name="code"> int a1[8][8]; for(int i=0;i<8;i ) { for(int j=0;j<8;j ) { a1[i][j] = random(2); } } for(int i=0;iHeight;i ) { for(int j=0;jWidth;j ) { if(a1[i%8][j%8]==1) Image3->Canvas->Pixels[i][j]=255; else Image3->Canvas->Pixels[i][j]=0; } } </textarea>

這樣是你要的嗎?

------
~§~迷時師渡，悟了自渡~§~

可以的,非常謝謝^^

------
加強磨鍊