unsignd char a;
a = 0xF0;
if (a & 0x01)
  printf("bit0 = 1);
if (a & 0x02)
  printf("bit1 = 1);
......以此類推

 
函數:
unsigned char* ToBinaryChar(unsigned char inputChar )  
  unsigned char c[8];
  for (int i=7; i>=0; i--)
  {
    c[i] = (inputChar & 0x01) ? '1' : '0';
    inputChar = inputChar >> 1;
  }
  return c;
}    使用:
unsigned char input = 0xF0; // Binary(11110000)
unsigned char bin[] = ToBinaryChar(input);  // bin[]="11110000"; 

引言:想請問一下喔..我宣告一個byte abc;byte 是一個8bit的integer,那要怎麼分別去讀這8 個bit的0或1阿

提供另一個方式，可單獨存取每一個bit < class="code"> #include #include typedef union { unsigned char byte; struct { unsigned char b0:1; unsigned char b1:1; unsigned char b2:1; unsigned char b3:1; unsigned char b4:1; unsigned char b5:1; unsigned char b6:1; unsigned char b7:1; }bit; }TEST; int main(int argc, char *argv[]) { TEST a; a.byte=0x0; a.bit.b0=1; a.bit.b1=0; a.bit.b2=1; a.bit.b7=1; printf("0x%x\n",a.byte); printf("sizeof=%d\n",sizeof(TEST)); system("PAUSE"); return 0; } ABSee數位相機族群的專業網站，免費1G 網路相簿 http://absee.com.tw/law.asp?uRef=15360