// Integer.h
#ifndef INTEGER_H
#define INTEGER_H    class Integer
{
public:
    Integer() {value = 0;}
    Integer( int intVal );        int getInteger() const;
    void setInteger( int newInteger );
    Integer& operator=( const Integer& rhInteger );
private:
    int value; // This line will be removed…
    // int* value; // and replaced with this one…
    // NOTE: You will only use ONE attribute
};    #endif    // Integer.cpp
#include “integer.h”        Integer::Integer( int intVal )
{
    value = intVal;
}    int Integer::getInteger() const
{
    return value;
}    void Integer::setInteger( int newInteger )
{
    value = newInteger;
}    Integer& Integer::operator=( const Integer& rhInt )
{
    value = rhInt.value;
    return *this;
}    // IntegerTest.cpp
#include 
#include 
#include “integer.h”    using namespace std;    void displayInteger( char* str, Integer intObj )
{
    cout << str << “ is “ << intObj.getInteger() << endl;
}    int main( int argc, char* argv[] )
{
    Integer intVal1;
    Integer intVal2(10);        displayInteger( “intVal1”, intVal1 );
    displayInteger( “intVal2”, intVal2 );
   
    intVal1 = intVal2;        displayInteger( “intVal1”, intVal1 );        return EXIT_SUCCESS;
}    第一部，我已把 int value; 轉了做 int* value;    但係我就唔明怎樣可以把呢個程序轉用 pointer 來做.
因為我吾係好識 pointer 同埋請問點樣加 copy constructor. 同 destructor?    請各位指點. 多謝各位大大