typedef struct
{
  int diff;    } MY_STRUCT  ;
int sort_function( const void *a, const void *b)
{
   MY_STRUCT *m1=(MY_STRUCT*)a;
   MY_STRUCT *m2=(MY_STRUCT*)b;
   if(m1->diff>m2->diff)
   {
      return 1;
   }
   else if(m1->diffdiff)
   {
      return -1;
   }
   else
   {
      return 0;
   }    }
//--------------------------------------------------------------------        void __fastcall TForm1::Btn_sortClick(TObject *Sender)
{
 vector d;
 MY_STRUCT tmp;
 tmp.diff=1;
 d.push_back(tmp);
 tmp.diff=100;
 d.push_back(tmp);
  tmp.diff=12;
 d.push_back(tmp);
 qsort(d,d.size(),sizeof(MY_STRUCT),sort_function);    }

為什麼會出現 cannot convert 'vector>'to 'void*' 的錯誤訊息 該如何解決呢?

我參考qsort的help void qsort(void *base, size_t nelem, size_t width, int (_USERENTRY *fcmp)(const void *, const void *)); base points to the base (0th element) of the table to be sorted. nelem is the number of entries in the table. width is the size of each entry in the table, in bytes. 我改成這樣... qsort((void *)&d[0],d.size(), sizeof(MY_STRUCT), sort_function); 但是我不確定對不對..因為這是我第一次用qsort這個函式，加上我的程式能力有點爛，請見諒^^