以前常玩的猜字母遊戲@@

老師會話一個人上吊的圖~~~

然後26個字母 去猜一個單子~~~


不過要寫程一個遊戲 我覺得好難阿


誰可以幫幫我


1.The computer randomly selects an English word from a list of at least 10 English words.

2.The computer randomly exposes some characters of an English word of the lenght n. At least 1 character is exposed and at maximum n - 1 character.

3.The player guesses character by character until the word is solved or the 8 times of wrong guesses is exceeded.

4.Each time a correct character is guessed the character is exposed.

5.They player can decide to continue to play or not.

Hint:

1.To get the string length, use the strlen function.

2.To compare two strings, use the strcmp function.

3.To count the number of strings, refer to the following code:



main() {



char *words[] = {"computer", "information", "engineering", "programming"};

char guess[30];

int i, n = sizeof(words)/sizeof(char *);



printf("List of string: ");

for (i = 0; i < n; i ) printf("%s ", words);



i = rand() % n;

printf("\nEnter your guess : ");

scanf("%s", guess);

printf("Your guess is \"%s\".\n", guess);

printf("Computer selects \"%s\".\n", words);

if (strcmp(guess, words)) printf("Your guess is wrong.\n");

else printf("Your guess is correct.\n");

}

A possible session could look like as follows:



The word to guess: -a--c

Your guess => o

The word to guess: -a--c

Your guess => m

The word to guess: ma--c

Your guess => l

The word to guess: ma--c

Your guess => g

The word to guess: mag-c

Your guess => i

Correct! The word is magic.

====================================================

Continue (Y/N)? Y

The word to guess: wo--e-

...

...

You guessed wrong more than 8 times. The word is wonder.

====================================================

Continue (Y/N)? N

Bye!






拜託一下了

以前常玩的猜字母遊戲@@

老師會話一個人上吊的圖~~~

然後26個字母 去猜一個單子~~~


不過要寫程一個遊戲 我覺得好難阿


誰可以幫幫我


1.The computer randomly selects an English word from a list of at least 10 English words.

2.The computer randomly exposes some characters of an English word of the lenght n. At least 1 character is exposed and at maximum n - 1 character.

3.The player guesses character by character until the word is solved or the 8 times of wrong guesses is exceeded.

4.Each time a correct character is guessed the character is exposed.

5.They player can decide to continue to play or not.

Hint:

1.To get the string length, use the strlen function.

2.To compare two strings, use the strcmp function.

3.To count the number of strings, refer to the following code:



main() {



char *words[] = {"computer", "information", "engineering", "programming"};

char guess[30];

int i, n = sizeof(words)/sizeof(char *);



printf("List of string: ");

for (i = 0; i < n; i ) printf("%s ", words);



i = rand() % n;

printf("\nEnter your guess : ");

scanf("%s", guess);

printf("Your guess is \"%s\".\n", guess);

printf("Computer selects \"%s\".\n", words);

if (strcmp(guess, words)) printf("Your guess is wrong.\n");

else printf("Your guess is correct.\n");

}

A possible session could look like as follows:



The word to guess: -a--c

Your guess => o

The word to guess: -a--c

Your guess => m

The word to guess: ma--c

Your guess => l

The word to guess: ma--c

Your guess => g

The word to guess: mag-c

Your guess => i

Correct! The word is magic.

====================================================

Continue (Y/N)? Y

The word to guess: wo--e-

...

...

You guessed wrong more than 8 times. The word is wonder.

====================================================

Continue (Y/N)? N

Bye!






拜託一下了