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MD5 演算法實例測試有誤?

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g6101
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#1 引用回覆 回覆 發表時間:2010-11-23 09:24:54 IP:59.112.xxx.xxx 訂閱
各位前輩:
我從站上找到 MD5 演算法的程式碼,做實例測試(6.7.)有誤(其他正確),反複檢查N遍,實在找不出問題處,特來請教。

測試資料
1.MD5 ("") = d41d8cd98f00b204e9800998ecf8427e
2.MD5 ("a") = 0cc175b9c0f1b6a831c399e269772661
3.MD5 ("abc") = 900150983cd24fb0d6963f7d28e17f72
4.MD5 ("message digest") = f96b697d7cb7938d525a2f31aaf161d0
5.MD5 ("abcdefghijklmnopqrstuvwxyz") = c3fcd3d76192e4007dfb496cca67e13b
6.MD5 ("ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789") =d174ab98d277d9f5a5611c2c9f419d9f
7.MD5 ("12345678901234567890123456789012345678901234567890123456789012345678901234567890")
=57edf4a22be3c955ac49da2e2107b67a

[code cpp]
////////////////////////////////////////////////////////////////////////////////
typedef struct {
DWORD state[4]; //encypted message
DWORD count[2]; //bits of plaintext
unsigned char buffer[64];
}MD5_CTX;

////////////////////////////////////////////////////////////////////////////////
#define S11 7
#define S12 12
#define S13 17
#define S14 22
#define S21 5
#define S22 9
#define S23 14
#define S24 20
#define S31 4
#define S32 11
#define S33 16
#define S34 23
#define S41 6
#define S42 10
#define S43 15
#define S44 21

#define a esi
#define b edi
#define c edx
#define d ebx
#define tmp1 eax
#define tmp2 ecx

#define x(i) [x 4*i]
static unsigned char PADDING[64] =
{
0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00
};

#define FF(a,b,c,d,x,s,ac)\
__asm mov tmp1,b;\
__asm and tmp1,c;\
__asm mov tmp2,b;\
__asm not tmp2;\
__asm and tmp2,d;\
__asm or tmp2,tmp1;\
__asm lea a,[tmp2 a ac];\
__asm add a,x;\
__asm rol a,s;\
__asm add a,b;

#define GG(a,b,c,d,x,s,ac)\
__asm mov tmp1,b;\
__asm and tmp1,d;\
__asm mov tmp2,d;\
__asm not tmp2;\
__asm and tmp2,c;\
__asm or tmp2,tmp1;\
__asm lea a,[tmp2 a ac];\
__asm add a,x;\
__asm rol a,s;\
__asm add a,b;

#define HH(a,b,c,d,x,s,ac)\
__asm mov tmp2,b;\
__asm xor tmp2,c;\
__asm xor tmp2,d;\
__asm lea a,[tmp2 a ac];\
__asm add a,x;\
__asm rol a,s;\
__asm add a,b;

#define II(a,b,c,d,x,s,ac)\
__asm mov tmp2,d;\
__asm not tmp2;\
__asm or tmp2,b;\
__asm xor tmp2,c;\
__asm lea a,[tmp2 a ac];\
__asm add a,x;\
__asm rol a,s;\
__asm add a,b;

static void MD5Transform(DWORD state[4],unsigned char block[64]);
static void MD5Init (MD5_CTX *context)
{
context->count[0] = context->count[1] = 0;
context->state[0] = 0x67452301;
context->state[1] = 0xefcdab89;
context->state[2] = 0x98badcfe;
context->state[3] = 0x10325476;
}

static void MD5Update(MD5_CTX *context,unsigned char *input,unsigned int inputLen)
{
unsigned int i,index,partLen;

index = (unsigned int)((context->count[0] >> 3) & 0x3F);
if ((context->count[0] = ((DWORD)inputLen << 3)) < ((DWORD)inputLen << 3)) {
context->count[1] ; }
context->count[1] = ((DWORD)inputLen >> 29);

partLen = 64 - index;
if (inputLen >= partLen) {
memcpy(&context->buffer[index],input,partLen);
MD5Transform(context->state,context->buffer);

for (i = partLen; i 63 < inputLen; i = 64) {<br /> MD5Transform(context->state,&input[i]);
}
index = 0;
} else {
i = 0;
}
/* Buffer remaining input */
memcpy(&context->buffer[index],&input[i],inputLen - i);
}

static void MD5Final(MD5_CTX *context,unsigned char res[/*16*/])
{
unsigned char *p=NULL;
unsigned char bits[8];
unsigned int i,index,padLen;

memcpy(bits,context->count,8);
index = (unsigned int)((context->count[0] >> 3) & 0x3f);
padLen = (index < 56)?(56 - index):(120 - index);
MD5Update(context,PADDING,padLen);
MD5Update(context,bits,8);

p=(unsigned char*)(&(context->state[0]));
for(i=0;i <16;i ) {
res[i]=*(p i); }
}

static void MD5Transform(DWORD state[4],unsigned char block[64])
{
DWORD x[16];
__asm
{
//initial
mov a,0x67452301
mov b,0xefcdab89
mov c,0x98badcfe
mov d,0x10325476
//copy string from block to state
//考慮到用API會影響寄存器,所以自己實現這一段記憶體拷貝
push esi
push edi

xor ecx,ecx
mov esi,dword ptr [block]
lea edi,[x]
ROLL:
mov eax,dword ptr [esi ecx]
mov dword ptr [edi ecx],eax
add ecx,4
cmp ecx,64
jb ROLL

pop edi
pop esi
}

/* Round 1 */
FF(a, b, c, d, x( 0), S11, 0xd76aa478); /* 1 */
FF(d, a, b, c, x( 1), S12, 0xe8c7b756); /* 2 */
FF(c, d, a, b, x( 2), S13, 0x242070db); /* 3 */
FF(b, c, d, a, x( 3), S14, 0xc1bdceee); /* 4 */
FF(a, b, c, d, x( 4), S11, 0xf57c0faf); /* 5 */
FF(d, a, b, c, x( 5), S12, 0x4787c62a); /* 6 */
FF(c, d, a, b, x( 6), S13, 0xa8304613); /* 7 */
FF(b, c, d, a, x( 7), S14, 0xfd469501); /* 8 */
FF(a, b, c, d, x( 8), S11, 0x698098d8); /* 9 */
FF(d, a, b, c, x( 9), S12, 0x8b44f7af); /* 10 */
FF(c, d, a, b, x(10), S13, 0xffff5bb1); /* 11 */
FF(b, c, d, a, x(11), S14, 0x895cd7be); /* 12 */
FF(a, b, c, d, x(12), S11, 0x6b901122); /* 13 */
FF(d, a, b, c, x(13), S12, 0xfd987193); /* 14 */
FF(c, d, a, b, x(14), S13, 0xa679438e); /* 15 */
FF(b, c, d, a, x(15), S14, 0x49b40821); /* 16 */

/* Round 2 */
GG(a, b, c, d, x( 1), S21, 0xf61e2562); /* 17 */
GG(d, a, b, c, x( 6), S22, 0xc040b340); /* 18 */
GG(c, d, a, b, x(11), S23, 0x265e5a51); /* 19 */
GG(b, c, d, a, x( 0), S24, 0xe9b6c7aa); /* 20 */
GG(a, b, c, d, x( 5), S21, 0xd62f105d); /* 21 */
GG(d, a, b, c, x(10), S22, 0x2441453); /* 22 */
GG(c, d, a, b, x(15), S23, 0xd8a1e681); /* 23 */
GG(b, c, d, a, x( 4), S24, 0xe7d3fbc8); /* 24 */
GG(a, b, c, d, x( 9), S21, 0x21e1cde6); /* 25 */
GG(d, a, b, c, x(14), S22, 0xc33707d6); /* 26 */
GG(c, d, a, b, x( 3), S23, 0xf4d50d87); /* 27 */
GG(b, c, d, a, x( 8), S24, 0x455a14ed); /* 28 */
GG(a, b, c, d, x(13), S21, 0xa9e3e905); /* 29 */
GG(d, a, b, c, x( 2), S22, 0xfcefa3f8); /* 30 */
GG(c, d, a, b, x( 7), S23, 0x676f02d9); /* 31 */
GG(b, c, d, a, x(12), S24, 0x8d2a4c8a); /* 32 */

/* Round 3 */
HH(a, b, c, d, x( 5), S31, 0xfffa3942); /* 33 */
HH(d, a, b, c, x( 8), S32, 0x8771f681); /* 34 */
HH(c, d, a, b, x(11), S33, 0x6d9d6122); /* 35 */
HH(b, c, d, a, x(14), S34, 0xfde5380c); /* 36 */
HH(a, b, c, d, x( 1), S31, 0xa4beea44); /* 37 */
HH(d, a, b, c, x( 4), S32, 0x4bdecfa9); /* 38 */
HH(c, d, a, b, x( 7), S33, 0xf6bb4b60); /* 39 */
HH(b, c, d, a, x(10), S34, 0xbebfbc70); /* 40 */
HH(a, b, c, d, x(13), S31, 0x289b7ec6); /* 41 */
HH(d, a, b, c, x( 0), S32, 0xeaa127fa); /* 42 */
HH(c, d, a, b, x( 3), S33, 0xd4ef3085); /* 43 */
HH(b, c, d, a, x( 6), S34, 0x4881d05); /* 44 */
HH(a, b, c, d, x( 9), S31, 0xd9d4d039); /* 45 */
HH(d, a, b, c, x(12), S32, 0xe6db99e5); /* 46 */
HH(c, d, a, b, x(15), S33, 0x1fa27cf8); /* 47 */
HH(b, c, d, a, x( 2), S34, 0xc4ac5665); /* 48 */

/* Round 4 */
II(a, b, c, d, x( 0), S41, 0xf4292244); /* 49 */
II(d, a, b, c, x( 7), S42, 0x432aff97); /* 50 */
II(c, d, a, b, x(14), S43, 0xab9423a7); /* 51 */
II(b, c, d, a, x( 5), S44, 0xfc93a039); /* 52 */
II(a, b, c, d, x(12), S41, 0x655b59c3); /* 53 */
II(d, a, b, c, x( 3), S42, 0x8f0ccc92); /* 54 */
II(c, d, a, b, x(10), S43, 0xffeff47d); /* 55 */
II(b, c, d, a, x( 1), S44, 0x85845dd1); /* 56 */
II(a, b, c, d, x( 8), S41, 0x6fa87e4f); /* 57 */
II(d, a, b, c, x(15), S42, 0xfe2ce6e0); /* 58 */
II(c, d, a, b, x( 6), S43, 0xa3014314); /* 59 */
II(b, c, d, a, x(13), S44, 0x4e0811a1); /* 60 */
II(a, b, c, d, x( 4), S41, 0xf7537e82); /* 61 */
II(d, a, b, c, x(11), S42, 0xbd3af235); /* 62 */
II(c, d, a, b, x( 2), S43, 0x2ad7d2bb); /* 63 */
II(b, c, d, a, x( 9), S44, 0xeb86d391); /* 64 */

__asm
{
mov tmp1,DWORD PTR [state]
add DWORD PTR [tmp1],a
add DWORD PTR [tmp1 4],b
add DWORD PTR [tmp1 8],c
add DWORD PTR [tmp1 12],d
}
}

//---------------------------------------------------------------------------
AnsiString __fastcall MD5_AnsiString(const AnsiString Input)
{
int ok=0;
MD5_CTX context;
unsigned char digest[16], tmp[3], res[33]={0};

try {
MD5Init (&context);
MD5Update (&context, Input.c_str(), Input.Length());
MD5Final (&context, digest);
ok = 1;
} catch(...) {
ok = 0;
}
if(ok == 1) {
for(int i=0;i <16;i ) {
sprintf(tmp,"X",digest[i]);
strncat(res,tmp,2); }
res[32]=0;
}
return AnsiString((char*)res);
}
//---------------------------------------------------------------------------
[/code]

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